The final volume of the air at 60 degree Celsius has been 1.8 L.
The relationship between the volume and temperature of a gas at constant pressure has been given by Charles Law.
The Charles Law has been expressed as:
[tex]\dfrac{V_1}{T_1} =\dfrac{V_2}{T_2}[/tex]
Computation for Volume of air
The given air has been assumed to be present at constant pressure. The temperature and volume of air has been given as:
The initial volume of the air, [tex]V_1=600\;\rm mL[/tex]
The initial temperature of air, [tex]T_1=20.0\;\rm ^\circ C[/tex]
The final temperature of air, [tex]T_2=60\;^\circ \rm C[/tex]
Substituting the values in the equation of Charles law for final volume, [tex]V_2[/tex]:
[tex]\dfrac{600}{20}=\dfrac{V_2}{60}\\V_2= \dfrac{600}{20}\;\times\;60\\V_2=1800\;\text{mL}\\V_2=1.8\;\rm L[/tex]
The final volume of the air at 60 degree Celsius has been 1.8 L.
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