Question

A 1.5 kg object is whirled around on the end of a string that is 1.8 m long. The object's linear speed is 5.6 m/s. What is the angular momentum of the object?

Answer 1

Answer: $15.12 \frac{kg m^{2}}{s}$

Explanation:

The angular momentum $L$ of an object is given by the following formula:

$L=rmV sin \theta$

Where:

$r=1.8 m$ is the distance between the object and the origin (the center of the circular motion)

$m=1.5 kg$ is the mass of the object

$V=5.6 m/s$ is the linear speed of the object

$\theta=90\°$ since the oject is moving in circular motion, $r$ is perpendicular to $mV$, which is the object's linear momentum.

Solving with the givrn data:

$L=(1.8 m)(1.5 kg)(5.6 m/s) sin(90\°)$

$L=15.12 \frac{kg m^{2}}{s}$ This is the object's angular momentum