Answer: a) 0.996, b) 0.253, c) 0.02.
Step-by-step explanation:
Since we have given that
Probability of success = Probability of the math majors belong to ethnic minorities = 33% = 0.33 =p
Probability of failure = q = 1-0.33 = 0.67
Number of students selected = 7
a) No more than 5 belong to an ethnic minority
So, using "binomial distribution", we get that
[tex]P(X\leq 5)=\sum^5 _{x=0} ^5C_x(0.33)^x(0.67)^{5-x}=0.996[/tex]
b. Exactly three of them belong to an ethnic minority
So, it becomes,
[tex]P(X=3)=^7C_3(0.33)^3(0.67)^4=0.253[/tex]
c. None of them belong to an ethnic minority
[tex]P(X=0)=^7C_0(0.33)^0(0.67)^7=0.02[/tex]
Hence, a) 0.996, b) 0.253, c) 0.02.