Question

4k+mn=n; solve each equation for the given variable; n

Answer 1

$4k+mn=n\ \ \ |Subtract\ mn\\\\ 4k=n-mn\ \ \ |Put\ n\ in\ front\ of\ the\ bracket\\\\ 4k=n(1-m) \ \ \ |Divide\ by\ (1-m)\\\\ \frac{4k}{1-m}=n\\\\ Solution\ is\ n= \frac{4k}{1-m}.$