Answer:
[tex]C) \:(1,0)[/tex]
Step-by-step explanation:
1) Let's find the Midpoint of IK and the Midpoint of HJ, for if there is a bisection then the midpoint is the first thing to look for.
[tex]M_{IK}=\left ( \frac{4-2}{2},\frac{3-3}{2} \right )=(1,0)\\M_{HJ}=\left ( \frac{-2+4}{2},\frac{2-2}{2} \right )=(1,0)[/tex]
2) Notice that both midpoints share the same value, which means the diagonals cross each other equally in two parts.
3) It is possible to show geometrically, that this is a parallelogram since both diagonals bisect each other indeed.
