Respuesta :
Answer:
A. 2 hours walking; 12 hours running
Step-by-step explanation:
The combination of hours walking and running has to respect both these inequalities:
[tex]3w + 6r \geq 36[/tex]
[tex]3w + 6r \leq 90[/tex]
A. 2 hours walking; 12 hours running
3w + 6r = 3*2 + 6*12 = 6+72 = 78.
Ok, it is larger than 35 and smaller than 91.
B. 4 hours walking; 3 hours running
3w + 6r = 3*4 + 6*3 = 12 + 18 = 30.
Invalid. Lesser than 36.
C. 9 hours walking; 12 hours running
3w + 6r = 3*9 + 6*12 = 27 + 72 = 99
Larger than 90. Invalid
D. 12 hours walking; 10 hours running
3w + 6r = 3*12 + 6*10 = 96
Larger than 90. Invalid
The combination of hours Keitaro can walk and run in a month to reach his goal is 2 hours walking; 12 hours running
3w + 6r ≥ 36. (1)
3w + 6r ≤ 90. (2)
substitute each option into the equation
A. 2 hours walking; 12 hours running
3w + 6r ≥ 36
3(2) + 6(12) ≥ 36
6 + 72 ≥ 36
78 ≥ 36
True
3w + 6r ≤ 90
3(2) + 6(12) ≤ 90
6 + 72 ≤ 90
78 ≤ 90
True
B. 4 hours walking; 3 hours running
3w + 6r ≤ 90
3(4) + 6(3) ≤ 90
12 + 18 ≤ 90
30 ≤ 90
True
B. 4 hours walking; 3 hours running
3w + 6r ≥ 36
3(4) + 6(3) ≥ 36
12 + 18 ≥ 36
30 ≥ 36
False
C. 9 hours walking; 12 hours running
3w + 6r ≥ 36
3(9) + 6(12) ≥ 36
27 + 72 ≥ 36
99 ≥ 36
True
3w + 6r ≤ 90
3(9) + 6(12) ≤ 90
27 + 72 ≤ 90
99 ≤ 90
False
D. 12 hours walking; 10 hours running
3w + 6r ≥ 36
3(12) + 6(10) ≥ 36
36 + 60 ≥ 36
96 ≥ 36
True
3w + 6r ≤ 90
3(12) + 6(10) ≤ 90
36 + 60 ≤ 90
96 ≤ 90
False.
Therefore, the combination of hours Keitaro can walk and run in a month to reach his goal is 2 hours walking; 12 hours running
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