Answer:
[tex]y=2\text{cos}((\frac{2\pi}{3})t)[/tex]
Step-by-step explanation:
We have been given that an object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seconds. We are asked to find the cosine function that can be used to model the height of the object.
We know that standard form of cosine function is [tex]y = A\cdot \text{cos}(Bt-C)+D[/tex], where,
|A| = Amplitude,
Period = [tex]\frac{2\pi}{|B|}[/tex],
C = Phase shift,
D = Vertical shift.
Since distance between maximum and minimum is 4, therefore, amplitude will be half of it, that is, [tex]A = 2[/tex].
Since objects gets back to its maximum value in every 3 seconds, therefore, period of the function is 3 seconds. We know that period is given by [tex]\frac{2\pi}{|B|}[/tex], therefore, we can write [tex]\frac{2\pi}{|B|}=3[/tex], therefore, [tex]B = \frac{2\pi}{3}[/tex].
We haven't been given any information about phase and mid-line, we can assume the values of C and D to be zero .
Therefore, our function required function would be [tex]y=2\text{cos}((\frac{2\pi}{3})t)[/tex].