Respuesta :

Answer:

[tex] \frac{5 {x}^{2} + 20xy + 20 {y}^{2} }{x ^{2} - xy - {6y}^{2} } [/tex]

To simplify first factorize both the numerator and the denominator

For the numerator

5x² + 20xy + 20y²

Factor 5 out

5 ( x² + 4xy + 4y²)

Using a² + 2ab + b² = ( a + b)²

The numerator is

5( x + 2y)²

For the denominator

x² - xy - 6y²

Rewrite -xy as a difference

x² + 2xy - 3xy - 6y²

Factorize

We have the denominator as

( x + 2y)( x - 3y)

So we now have

[tex] \frac{5(x + 2y)(x + 2y)}{(x + 2y)(x - 3y)} [/tex]

Simplify

[tex] \frac{5(x + 2y)}{x - 3y} [/tex]

We have the final answer as

[tex] \frac{5x + 10y}{x - 3y} [/tex]

Hope this helps you

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