Question

Miriam is playing a game of dice. For every 1 or 6 rolled, Miriam will in $5. For any other number, she must pay $2. How much money can Miriam except to win or lose?

Answer 1

Answer:

So, she can expect to win a total of $0.33 .

Step-by-step explanation:

According to the question miriam will get 5$ when the dice will show 1 or 6 .

And also she will lose 2$ for any other number .

Now ,

Total number of favorable cases for winning of 5$ for the miriam are 2.

Total number of cases = 6.

Also,

Total number of cases in which she will lose money will be 4.

So, probability of win = $\frac{2}{6}$.

Probability of loss = $\frac{4}{6}$.

Thus ,

Total amount of money that she can expect to win =

$\frac{2}{6}$×5 - $\frac{4}{6}$×2 = $\frac{1}{3}$.

So, she can expect to win a total of $0.33 .