Question

Quaker Oatmeal is a very popular breakfast cereal. If Susan wrapped the entire container without any overlapping paper, what is the minimum amount of paper she will need to wrap the entire container

11cm tall
with a width of 6cm

Answer 1

263.76 cm is the minimum amount of paper she will need to wrap the entire container.

Step-by-step explanation:

As we know that the equation for surface area of a cylinder,

Surface area of cylinder =  $2\pi r^{2}+2 \pi r h$

Where,

r - the radius of the cylinder. Here given diameter (D) as 6. So,

          $r=\frac{D}{2}=\frac{6}{2}=3 \mathrm{cm}$

h - the height of the cylinder (given as 11 cm). The value for pi = 3.14. Now, calculate the surface area of the cylinder as

                     $A=2(3.14)(3)^{2}+2(3.14)(3)(11)$

                            A = 56.52+ 207.24 = 263.76 cm