Question

A 55-kg woman is wearing high heels.
If each heel has a circular cross-section 6.0 mm in diameter and she puts all her weight on one heel, how much pressure does that exert on the floor?

a)4.9 x 105 Pa

b)1.9 x 10 Pa

c)4.8 x 106 Pa

d)1.9 x 105 Pa

e)1.2 x 105 Pa

Answer 1

Answer:

Pressure, $P=1.90\times 10^7\ Pa$        

Explanation:

It is given that,

Mass of the woman, m = 55 kg

Diameter of the circular cross section, d = 6 mm

Radius, r = 3 mm = 0.003 m

Let P is the pressure exerted on the floor. It is equal to the force acting on woman per unit area. It is given by :

$P=\dfrac{F}{A}$

$P=\dfrac{mg}{\pi r^2}$

$P=\dfrac{55\times 9.8}{\pi (0.003)^2}$

$P=1.90\times 10^7\ Pa$

So, the pressure exerted on the floor is $1.90\times 10^7\ Pa$. Hence, this is the required solution.