10 POINTS
Find the surface area of the solid shown or described. If necessary, round to the nearest tenth.

10 POINTS Find the surface area of the solid shown or described If necessary round to the nearest tenth class=

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Answer:

[tex]484 {m}^{3} [/tex]

Step-by-step explanation:

applying Pythagorean theorem

[tex](7.1)^{2} + {x}^{2} = 14.6^{2} \\ then \\ {x}^{2} = 14.6^{2} - 7.1^{2} \\ {x}^{2} = 162.72 \\ x = \sqrt{162.72} \\ x = 12.7573m[/tex]

area of a cone :

[tex]\pi \: r(r + \sqrt{( {h}^{2} + {r}^{2} )} )[/tex]

substitute r and h

A =484.02

Answer:

484 m²

Step-by-step explanation:

The figure is composed of a circular end and a curved surface

area of circle = πr² ← r is the radius

A = π × 7.1² = 158.37 m²

area of curved surface = πrs ← s is the slant height

here s = 14.6, thus

A = π × 7.1 × 14.6 = 325.66 m²

Surface area = 158.37 + 325.66 ≈ 484 m²

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