How would I do this? What would it be?

50
Step-by-step explanation:
Since AE is the bisector of angle BAC,so angle BAE and Angle CAE is equal. Here Angle CAE and Angle EAC is same.
therefore,
m(Angle BAE)=m(Angle EAC)
[tex]x + 30 = 3x - 10 [/tex]
or, 2x=40
or, x=20
Hence,
m(Angle EAC)=
[tex]3x - 10[/tex]
=
[tex](3 \times 20) - 10 = 60 - 10 = 50[/tex]
Answer:
Step-by-step explanation:
You can solve this by substitution method
Since AE is bisector
Angle BAE = angle. EAC
SINCE angle BAE=x+30
EAC= x+30
So, 3x-10= x+30
2x. = 40
x. = 40/2 = 20°
Thank you