The measurement is closest to the distance, in meters, of jeffs starting point d3 is 59.1 meters
We have given data
d1 = 54 m
d2 = 24 m
d3 = ?
What is the formula for the Pythagorean theorem?
The Pythagorean theorem
[tex]hypotenous^2=side^2+side^2[/tex]
d3² = d1² + d2²
Substitution
d3² = 54² + 24²
Simplifying above we get,
d3² = 2916 + 576
d3² = 3492
d3 = 59.1 m
Therefore, measurement is closest to the distance, in meters, of jeffs starting point d3 is 59.1 meters
Option b is correct.
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