Question

The magnetization within a bar of some metal alloy is 3.3 ×105 A/m at an H field of 61 A/m. Determine the following: (a) the magnetic susceptibility, (b) the permeability, and (c) the magnetic flux density within this material. (d) What type(s) of magnetism would you suggest as being displayed by this material?

Answer 1

Explanation:

(a) We calculate the magnetic susceptibility within a bar of metal alloy when M = 3.3 x 10⁶ A/m and H =61 A/m.  Solving for Xm gives  

Xm=M/H

Xm=3.3 x 10⁶/61

Xm=54098.4

(b) In order to calculate the permeability we employ

µ=µr µ₀

µ= µ₀(1+Xm)  

µ= 1.257x 10⁻⁶(1+ 54098.4)

µ=0.068 H/m

 

(c) The magnetic induction B may then be found from  

             B = µH = (0.068)(61) = 4.148Tesla

 

(d) This metal alloy would exhibit ferromagnetic behavior on the basis of its χm value (54098.4), which is considerably larger than typical χm values for diamagnetic and paramagnetic materials.  Also M is nonzero and large. (It could also be ferrimagnetic).