Question

What are the vertices of (AABC)when it is translated by x-6, y2), graph thetransformation?A'B'С

Answer 1

$\begin{gathered} A^{\prime}(0,0) \\ B^{\prime}(4,2) \\ C^{\prime}(2,-6) \end{gathered}$

Explanation

Step 1

get the coordinates of each point.

Let

$\begin{gathered} A=(-6,2) \\ B=(-2,4) \\ C=(-4,-4) \end{gathered}$

Step 2

now, to get the image apply the rule

$(x,y)\rightarrow(x+6,y-2)$

then

$\begin{gathered} A(-6,2)\rightarrow A´(-6+6,2-2)\rightarrow A^{\prime}(0,0) \\ B(-2,4)\rightarrow B^{\prime}(-2+6,4-2)\rightarrow B^{\prime}(4,2) \\ C(-4,-4)\rightarrow C^{\prime}(-4+6,-4-2)\rightarrow C^{\prime}(2,-6) \end{gathered}$

I hope this helps you