Respuesta :
Answer:
100.75 liters
Step-by-step explanation:
Data provided in the question:
t (min) 0 0.5 1 1.5 2 2.5 3
r (l/min) 44 40 37 34 30 27 23
Now,
left endpoint approximation
= 0.5 × ( 44 + 40 + 37 + 34 + 30 + 27 )
= 0.5 × 212
= 106
Right endpoint approximation
= 0.5 × ( 40 + 37 + 34 + 30 + 27 + 23 )
= 0.5 × 191
= 95.5
Therefore,
the average of the left- and right-endpoint approximations
= [ 106 + 95.5 ] ÷ 2
= 100.75 liters
The total amount of water drained during the first 3 min is: 100.75 liters/min.
Total amount of water
Left endpoint approximation
r = 1/2 ( 44 + 40 + 37 + 34 + 30 + 27 )
r= 1/2 × 212
r= 106 L/m
Right endpoint approximation
r= 1/2 × ( 40 + 37 + 34 + 30 + 27 + 23 )
r= 1/2 × 191
r= 95.5 L/min
Average of the left- and right-endpoint approximations
Average= [ 106 + 95.5 ] ÷ 2
Average=201.5÷2
Average= 100.75 liters/min
Inconclusion the total amount of water drained during the first 3 min is: 100.75 liters/min.
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