Question

The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 5 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 4.25 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.

Answer 1

Answer:

0.15 = 15% probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

$P(X > x) = \frac{b - x}{b - a}$

Uniformly distributed between 0 and 5 minutes.

This means that $a = 0, b = 5$

Find the probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.

$P(X > 4.25) = \frac{5 - 4.25}{5 - 0} = 0.15$

0.15 = 15% probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.