Question

An experiment is conducted using nitrogen monoxide and bromine reacted to form nitrosyl bromide. Calculate Keq for the reaction using the following equation data. [NOBr] = 0.0474 mol/L [NO] = 0.312 mol/L [Br2] = 0.259 mol/L Keq =

Answer 1

Answer:

The equilibrium coefficient of the reaction is 0.0891.  

Explanation:

The balanced chemical reaction from the given data is as follows.

$2NO+Br_{2}\rightarrow 2NOBr$

$K_{eq}=\frac{[NOBr]^{2}}{[NO]^{2}[Br_{2}]}$

From the given data,

[NOBr] = 0.0474 mol/L

[NO] = 0.312 mol/L

$[Br_{2}]=0.259 mol/L$

Substitute the all given values into the $K_{eq}$ formula.

$K_{eq}=\frac{(0.0474)^{2}}{(0.312)^{2}(0.259)}=0.0891$

Therefore, The equilibrium coefficient of the reaction is 0.0891.