Question

Find the equation of the line that is perpendicular to y=1/6x+3
and contains the point (-3,23).
y = [?]x + [?]

Answer 1

Answer:

y = -6x + 6

Step-by-step explanation:

The general equation of a line is

y = mx + b

where m is the slope and b is the y-intercept

The slope in the first equation is 1/6

Mathematically, when two lines are perpendicular, the product of their slopes is -1

1/6 * m2 = -1

m2 = -6

So we have the equation as;

y-y1 = m(x-x1)

y-23 = -6(x + 3)

y = -6x -18 +23

y = -6x + 6