Question

The demand function for a certain make of replacement cartridges for a water purifier is given by the following equation where p is the unit price in dollars and x is the quantity demanded each week, measured in units of a thousand.
p = −0.01x^2 − 0.1x + 21
1. Determine the consumers' surplus if the market price is set at $1/cartridge. (Round your answer to two decimal places.)

Answer 1

Answer:

The consumer surplus is $ 506.67 when the market price is set at $1 per cartridge.

Step-by-step explanation:

In order to find the Consumer Surplus we need to find first the quantity  at  which we have the market price.

Equilibrium quantity.

We can use the given price of $1 for each cartridge on the demand function  to get

$1=-0.01x^2-0.1x+21$

And we can move all terms to the left side.

$0.01x^2+0.1x+1-21=0\\0.01x^2+0.1x-20=0$

Then we can multiply all terms of both sides by 100 to get rid of the decimals.

$x^2+10x-200=0$

And we can work with factorization, such we need to think of what couple of numbers multiplied give us the last term, -200, but their sum must give us the middle coefficient, +10.

Those numbers are +50 and -40, so we get

$(x-50)(x+40)=0$

Setting each factor equal to 0.

$x = -50  \qquad and \qquad x = 40$

Thus the equilibrium quantity is 40 units per week.

Consumer surplus

We can use the given market price  and the quantity we have found on the following equation.

$C_s =\displaystyle \int_0^{x_e} (D(x) -p_e )dx$

Replacing the values and equation.

$C_s =\displaystyle \int_0^{40} (-0.01x^2-0.1x+21 -1 )\,dx$

Simplifying

$C_s =\displaystyle \int_0^{40} (-0.01x^2-0.1x+20 )\,dx$

Integrating each term.

$C_s =\displaystyle \left(-\cfrac{0.01}3x^3-\cfrac{0.1}2x^2+20x \right)_0^{40}$

And we can evaluate at the interval.

$C_s =\displaystyle \left(-\cfrac{0.01}3(40)^3-\cfrac{0.1}2(40)^2+20(40)-\left(-\cfrac{0.01}3(0)^3-\cfrac{0.1}2(0)^2+20(0) \right) \right)$

Finally arriving to

$\boxed{C_s =506.67}$

Thus consumer surplus is $ 506.67 when the market price is set at $1 per cartridge.