I need help on this problem
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Answer: [tex]QR=4.04[/tex]
Step-by-step explanation:
For this exercise you must use the followinG Trigonometric Identity:
[tex]tan\alpha=\frac{opposite}{adjacent}[/tex]
In this case, given the right triangle PQR, you can identify that:
[tex]\alpha=60\°\\opposite=PR=7.0\\adjacent=QR[/tex]
Then, the next step is to substitute those values into [tex]tan\alpha=\frac{opposite}{adjacent}[/tex]:
[tex]tan(60\°)=\frac{7.0}{QR}[/tex]
And the final step is to solve for "QR" in order to find its value.
So you get that this is:
[tex](QR)(tan(60\°))=7.0\\\\QR=\frac{7.0}{tan(60\°)}\\\\QR=4.04[/tex]