Question

WILL NAME BRAINLIEST!

The probability of drawing two red balls from a jar at random without replacement is 3/10. The probabilty of drawing a red ball first is 9/16.

What is the probability of drawing a second Redball, given that the first ball drawn was red?

A. 69/80

B. 8/15

C. 21/80

D. 27/160

Answer 1

Answer:

B. $p = \frac{8}{15}$

Step-by-step explanation:

The probability of selecting a red and then a red without replacement is as follows:

$\frac{9x}{16} * \frac{9x}{16} -1$

This equals the given probability of $\frac{3}{10}$

More simply, we have the equaiton:

$\frac{9}{16} * P = \frac{3}{10}$

So, $p = \frac{8}{15}$