Answer:
The mean nicotine content is higher than the industry laboratory claims at the 5% level.
The mean nicotine content is higher than the industry laboratory claims at the 1% level.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 1.4 milligrams
a) First, we design the null and the alternate hypothesis
[tex]H_{0}: \mu = 1.44\text{ milligrams of nicotine}\\H_A: \mu > 1.44\text{ milligrams of nicotine}[/tex]
We use One-tailed(right) z test to perform this hypothesis.
b) Formula:
[tex]z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }[/tex]
z = 2.36
Now, [tex]z_{critical} \text{ at 0.05 level of significance } = 1.64[/tex]
Since,
[tex]z_{stat} > z_{critical}[/tex]
We reject the null hypothesis and accept the alternate hypothesis. Thus, the mean nicotine content is higher than the industry laboratory claims at the 5% level.
c) Now, [tex]z_{critical} \text{ at 0.01 level of significance } = 2.33[/tex]
Since,
[tex]z_{stat} > z_{critical}[/tex]
We reject the null hypothesis and accept the alternate hypothesis. Thus, the mean nicotine content is higher than the industry laboratory claims at the 1% level.