Question

Which expression gives the mass percent of carbon in methanoic (formic) acid, HCOOH?12/46 x 10012/29 x 10016/46 x 1002/46 x 100

Answer 1

Answer:

$\frac{12}{46}\times100$

Explanation:

Molecular mass of methanoic acid (HCOOH) = 2*1 + 1*12 + 2*16

                                                                              =46 grams

mass of 1 mole of hydrogen atom = 1  g

mass of 1 mole carbon atom = 12 g

mass of 1 mole of oxygen atom = 16 g

mass of 1 mole of HCOOH = 46 g

1 mole of HCOOH molecule contains 1 mole of carbon atoms

means in 46 g of HCOOH there is 12 g of carbon atoms.

Percentage of carbon in methanoic acid = $\frac{12}{46}\times100$