Question

A disk of radius R = 11 cm is pulled along a frictionless surface with a force of F = 16 N by a string wrapped around the edge.At the instant when d = 30 cm of string has unwound off the disk, what is the torque exerted about the center of the disk?

Answer 1

Answer: 1.76 Nm

Explanation:

If the force pulls horizontally, this means that the force is tangent to the disk at any point of the string unwinding process, so the distance d is irrelevant.

In this case, the torque is directly given by the product of the force times the distance perpendicular to the center of the disk, which is just the radius, as follows:

τ = F * r = 16 N. (0.11) m = 1.76 Nm

Answer 2

The torque exerted on the center of the disk is mathematically given as

t = 1.76 Nm

What is the torque exerted on the center of the disk?

Question Parameter(s):

A disk of radius R = 11 cm is pulled along a frictionless surface with a force of F = 16 N

At the instant when d = 30 cm of string has unwound off the disk

Generally, the equation for the Torque   is mathematically given as

t = F * r

t= 16 N. (0.11) m

t = 1.76 Nm

In conclusion, the torque exerted on the center of the disk
t = 1.76 Nm

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