Question

Question 1(Multiple Choice Worth 1 points) (01.04 LC) Solve for x: −3x + 3 < 6 x > −1 x < −1 x < −3 x > −3

Answer 1

For this case we must resolve the following inequality:

$-3x + 3 <6$

To do this we follow the steps below:

Subtracting 3 from both sides of the inequality:

$-3x <6-3\\-3x <3$

Dividing by 3 to both sides of the inequality:

$-x <\frac {3} {3}\\-x <1$

We multiply by -1 on both sides taking into account that the sense of inequality changes:

$x> -1$

Thus, the solution is given by all values of x greater than -1.

Answer:

$x> -1$