Answer:
1/2
Explanation:
The allele for the red-green color blindness is X-linked recessive. The father of the woman was colorblind (X^cY) which means that the woman is a carrier for the allele and has genotype (X^cX). The genotype of the colorblind male would be X^cY. A cross between a carrier woman and a color-blind man would produce progeny in following ratio= 1/2 colorblind daughter: 1/2 normal daughter: 1/2 colorblind son: 1/2 normal son.
Therefore, there is a 50% probability that their first son is colorblind.