Question

Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing copper and silver. Cu ( s ) ∣ ∣ Cu 2 + ( aq ) ∥ ∥ Ag + ( aq ) ∣ ∣ Ag ( s ) anode: cathode: net cell reaction:

Answer 1

Answer: The half reactions and net cell reaction of the cell is written below.

Explanation:

The given cell is:

$Cu(s)/Cu^{2+}(aq.)||Ag^{+}(aq.)/Ag(s)$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

Half reactions for the given cell follows:

Oxidation half reaction (anode): $Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-$

Reduction half reaction (cathode): $Ag^{+}(aq.)+e^-\rightarrow Ag(s)$   ( × 2)

Net cell reaction:  $Cu(s)+2Ag^+(aq.)\rightarrow Cu^{2+}(aq.)+2Ag(s)$

Hence, the half reactions and net cell reaction of the cell is written above.