Question

The goose has a mass of 19.2 lb (pounds) and is flying at 7.10 miles/h (miles per hour). What is the kinetic energy of the goose in joules? Enter your answer numerically in joules.

Answer 1

Answer:

43.868 J

Explanation:

Kinetic energy of a body is the amount of energy possessed by a moving body. The SI unit of kinetic energy is the joule (kg⋅m²⋅s⁻²).

According to classical mechanics, kinetic energy = 1/2 m·v²

Where, m= mass in kg and v= velocity in m/s

Given: m = 19.2 lb and v = 7.10 miles/h

Since, 1 lb= 0.453592 kg

∴ m = 19.2 lb = 19.2 × 0.453592 kg = 8.709 kg

Also, 1 mi = 1609.34 m and 1 h = 3600 sec

∴ v = 7.10 mi/h = 7.10 × 1609.34 m ÷ 3600 sec = 3.174 m/sec

Therefore, kinetic energy of the goose = 1/2 m·v² = 1/2 × (8.709 kg)× (3.174 m/sec)² = 43.868 J

Answer 2

The kinetic energy of the goose of mass 19.2 lb flying at 7.10 mph is 48.868 J

• We'll begin by converting 19.2 lb to kilogram (Kg)

1 lb = 0.453592 Kg

Therefore,

19.2 lb = 19.2 × 0.453592

19.2 lb = 8.709 Kg

• Next, we shall convert 7.10 mph to m/s. This can be obtained as follow:

1 mph = 0.44704 m/s

Therefore,

7.10 mph = 7.10 × 0.44704

7.10 mph = 3.174 m/s

• Finally, we shall determine the kinetic energy of the goose. This can be obtained as follow:

Mass (m) = 8.709 Kg

Velocity (v) = 3.174 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 8.709 × 3.174²

KE = 48.868 J

Therefore, the kinetic energy of the goose is 48.868 J

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