Respuesta :

gmany

Answer:

[tex]\large\boxed{y-3=-(x+4)}\\or\\\boxed{y+4=-(x-3)}[/tex]

Step-by-step explanation:

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

(x₁, y₁) - point on a line

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have two points (-4, 3) and (3, -4).

Substitute:

[tex]m=\dfrac{-4-3}{3-(-4)}=\dfrac{-7}{7}=-1[/tex]

Put the value of a slope and the coordiantes of the point (-4, 3) or (3, -4) to the equation of a line:

for (-4, 3)

[tex]y-3=-1(x-(-4))\\\\y-3=-(x+4)[/tex]

for (3, -4)

[tex]y-(-4)=-1(x-3)\\\\y+4=-(x-3)[/tex]

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