Answer:
12920
Step-by-step explanation :
distance covered = d = ∫[tex]\int\limits^a_b ({sqrt{f'(t)^{2} +g'(t)^2\\}}) \, dt[/tex]
a = t = 20
b = t = 0
f'(t) = 646 : f'(t)² = 417316
g'(t) = 5 : g'(t)² = 25
d = [tex]\int\limits^a_b {646} \, dt[/tex]
t = 20 & t = 0
d = 646t
d = 646*20 = 12920