Question

A line intersects the points (-22, -14) and
(-18, -12). What is the slope-intercept
equation for this line?
y = 4x+

Answer 1

Answer:

$y=\frac{1}{2}x-3$

Step-by-step explanation:

we know that

The equation of the line in slope intercept form is

$y=mx+b$

where

m is the slope or unit rate

b is the y-intercept or initial value

step 1

Find the slope

we have the points

(-22, -14) and  (-18, -12)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values in the formula

$m=\frac{-12+14}{-18+22}$

$m=\frac{2}{4}$

simplify

$m=\frac{1}{2}$

step 2

Find the y-intercept b

we have

$m=\frac{1}{2}$

$point\ (-22,-14)$

substitute

$y=mx+b$

$-14=\frac{1}{2}(-22)+b$

solve for b

$-14=-11+b$

$b=-14+11$

$b=-3$

substitute

$y=\frac{1}{2}x-3$