The equation of the line is given by:
[tex]y - 1 = \frac{3}{2}(x+3)[/tex]
Which is the fourth option.
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The equation of line, in point-slope form, is given by:
[tex]y - y_0 = m(x - x_0)[/tex]
In which:
- m is the slope, that is, the rate of change.
- The point is [tex](x_0,y_0)[/tex]
- If two lines are parallel, they have the same slope.
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- The given line has two points, (-2,-4) and (2,2).
- The slope is given by the change in y divided by the change in x.
- Change in y: -2 - (-4) = 2 + 4 = 6
- Change in x: 2 - (-2) = 2 + 2 = 4
- Slope: [tex]m = \frac{6}{4} = \frac{3}{2}[/tex]
Thus:
[tex]y - y_0 = \frac{3}{2}(x - x_0)[/tex]
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- Point (-3,1) means that [tex]x_0 = -3, y_0 = 1[/tex], and thus:
[tex]y - y_0 = \frac{3}{2}(x - x_0)[/tex]
[tex]y - 1 = \frac{3}{2}(x - (-3))[/tex]
[tex]y - 1 = \frac{3}{2}(x+3)[/tex]
Fourth option.
A similar problem is given at https://brainly.com/question/22532445