What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−3, 1)?

y – 1=Negative three-halves(x + 3)
y – 1=Negative two-thirds(x + 3)
y – 1= Two-thirds(x + 3)
y – 1= Three-halves(x + 3)

What is the equation in pointslope form of the line that is parallel to the given line and passes through the point 3 1 y 1Negative threehalvesx 3 y 1Negative t class=

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Answer:

D). y – 1= Three-halves(x + 3)

Step-by-step explanation:

Took the test

The equation of the line is given by:

[tex]y - 1 = \frac{3}{2}(x+3)[/tex]

Which is the fourth option.

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The equation of line, in point-slope form, is given by:

[tex]y - y_0 = m(x - x_0)[/tex]

In which:

  • m is the slope, that is, the rate of change.
  • The point is [tex](x_0,y_0)[/tex]
  • If two lines are parallel, they have the same slope.

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  • The given line has two points, (-2,-4) and (2,2).
  • The slope is given by the change in y divided by the change in x.
  • Change in y: -2 - (-4) = 2 + 4 = 6
  • Change in x: 2 - (-2) = 2 + 2 = 4
  • Slope: [tex]m = \frac{6}{4} = \frac{3}{2}[/tex]

Thus:

[tex]y - y_0 = \frac{3}{2}(x - x_0)[/tex]

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  • Point (-3,1) means that [tex]x_0 = -3, y_0 = 1[/tex], and thus:

[tex]y - y_0 = \frac{3}{2}(x - x_0)[/tex]

[tex]y - 1 = \frac{3}{2}(x - (-3))[/tex]

[tex]y - 1 = \frac{3}{2}(x+3)[/tex]

Fourth option.

A similar problem is given at https://brainly.com/question/22532445

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