Answer:m=86.36 kg
Explanation:
Given
mass of tackler [tex]m_T=100 kg[/tex]
initial velocity of Tackler [tex]u_t=4.1 m/s[/tex]
Final velocity of combined system [tex]v=2.2 m/s[/tex]
Let m be the mass of receiver
conserving momentum
[tex]m\times 0+m_t\times u_t=(m+m_t)v[/tex]
[tex]0+100\times 4.1=(100+m)\cdot 2.2[/tex]
[tex]410=(100+m)\cdot 2.2[/tex]
[tex]100+m=186.36[/tex]
[tex]m=86.36 kg[/tex]