Respuesta :

Answer:

[tex]A=782\ yd^2[/tex]

Step-by-step explanation:

The area of the figure is equal to the area of four right triangles

so

The area of one right triangle is equal to

[tex]A=\frac{1}{2}(23)(17)[/tex]

[tex]A=195.5\ yd^2[/tex]

Multiply by 4

[tex]A=(4)195.5=782\ yd^2[/tex]

Alternative Method

The figure is a Rhombus

The area of the Rhombus is equal to

[tex]A=\frac{1}{2}(D_1)(D_2)[/tex]

where

D1 and D2 are the diagonals of the rhombus

we have

[tex]D_1=(23+23)=46\ yd\\D_2=(17+17)=34\ yd[/tex]

substitute

[tex]A=\frac{1}{2}(46)(34)[/tex]

[tex]A=782\ yd^2[/tex]

Answer:

782yd^2 is correct.

Step-by-step explanation:

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