sequences kind of confuse me, so could someone help?

Answer:
C
Step-by-step explanation:
Consider the number of triangles in each diagram
1 → 1 → [tex]2^{0}[/tex]
2 → 2 → [tex]2^{1}[/tex]
3 → 4 → 2²
4 → 8 → 2³
The pattern of triangles is 1, 2, 4, 8, that is
[tex]2^{0}[/tex], [tex]2^{1}[/tex], 2², 2³
Note that the exponent is one less than the figures position in the pattern, thus
[tex]a_{n}[/tex] = [tex]2^{n-1}[/tex] → C