Question

A roulette wheel has 38 slots in which the ball can land. Two of the slots are green, 18 are red, and 18 are black. The ball is equally likely to land in any slot. The roulette wheel is going to be spun twice, and the outcomes of the two spins are independent. The probability that the ball lands on black the first time and on green the second time is:

Answer 1

Answer: Our required probability is 0.0249.

Step-by-step explanation:

Since we have given that

Number of red slots = 18

Number of black slots = 18

Number of green slots = 2

total number of slots = 38

Since two spins are independent.

So, probability that the ball lands on black the first time and on green the second time is given by

$\dfrac{18}{38}\times \dfrac{2}{38}\\\\=\dfrac{36}{1444}\\\\=0.0249$

Hence, our required probability is 0.0249.