An airplane in the earth’s magnetic field can develop a voltage between its wingtips.

Find this voltage if the plane has a velocity v = 250 m/s pointing due North, the earth’s magnetic field B = 0.5 G points 30◦ below due North, and the plane’s wingspan is 20 m.


Which wingtip (left or right) is at a higher electric potential?

Respuesta :

Answer:

[tex]emf=0.125\ V[/tex]

According to the Fleming's Left left hand rule we have higher potential on the right edge of the wing.

Explanation:

Given:

  • velocity of plane, [tex]v=250\ m.s^{-1}[/tex]
  • magnetic field, [tex]B=5\times 10^{-5}\ T[/tex]
  • angle between velocity and magnetic field, [tex]\theta=30^{\circ}[/tex]
  • span of the wing, [tex]l=20\ m[/tex]

We know:

[tex]emf=B.l.v\ sin\theta[/tex]

[tex]emf=5\times 10^{-5}\times 20\times 250\times sin30^{\circ}[/tex]

[tex]emf=0.125\ V[/tex]

According to the Fleming's Left left hand rule we have higher potential on the right edge of the wing.

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