Answer:
[tex]emf=0.125\ V[/tex]
According to the Fleming's Left left hand rule we have higher potential on the right edge of the wing.
Explanation:
Given:
We know:
[tex]emf=B.l.v\ sin\theta[/tex]
[tex]emf=5\times 10^{-5}\times 20\times 250\times sin30^{\circ}[/tex]
[tex]emf=0.125\ V[/tex]
According to the Fleming's Left left hand rule we have higher potential on the right edge of the wing.