Answer: Option 'd' is correct.
Step-by-step explanation:
Since we have given that
Researcher A :
Mean = 12.4
Standard deviation = 9
sample size = 30
So, the standard error is given by
[tex]\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{9}{\sqrt{30}}\\\\=1.643[/tex]
Researcher B:
Mean = 12.4
Standard deviation = 9
Sample size = 40
So, the standard error is given by
[tex]\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{9}{\sqrt{40}}\\\\=1.423[/tex]
Sample B has smaller standard error than sample A because the sample size was larger than A.
Hence, Option 'd' is correct.