Answer:
The radius of the spool is 3.7 cm
Step-by-step explanation:
Consider the provided information.
The rate is 59.4 cm per sec and it makes 152 revolutions per min.
We need to find the radius.
Now use the formula: [tex]r=\frac{v}{\omega}[/tex]
Substitute [tex]\omega=152\ and\ v=59.4[/tex] in above formula and change the revolutions per min to rad per second.
[tex]r=59.4\frac{cm}{sec}(\frac{1}{152}\times \frac{min}{rev}\times\frac{60sec}{1min}\times\frac{1rev}{2\pi rad})[/tex]
[tex]r=\frac{3564}{304\pi}cm[/tex]
[tex]r\approx 3.7cm[/tex]
Hence, the radius of the spool is 3.7 cm