Answer:
4.59 moles of [tex]CO_{2}[/tex]
Explanation:
1. The reaction of combustiono of carbon monoxide CO in oxygen gas is:
[tex]2CO(g)+O_{2}(g)=2CO_{2}(g)[/tex]
2. Use the stoichiometry of the reaction to calculate the number of moles of [tex]CO_{2}[/tex] produced.
The problem says that there are enough oxygen gas to react with all the carbon monoxide CO, it means that the carbon monoxide CO is the limiting reagent, so the calculations will be made from the quantity of carbon monoxide CO, that is:
[tex]4.59molesCO*\frac{2molesCO_{2}}{2molCO}=4.59molesCO_{2}[/tex]