In a test strength at a carnival, a hammer drives a metal weight up a rod to ring a bell at the top. If the bell is 24 ft above the starting position of the weight, what is the minimum initial vertical velocity needed to ring the bell?
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Answer:
39 ft/s
Explanation:
Given:
Δy = 24 ft
v = 0 ft/s
a = -32 ft/s²
Find: v₀
v² = v₀² + 2aΔy
(0 ft/s)² = v₀² + 2 (-32 ft/s²) (24 ft)
v₀ ≈ 39 ft/s