Question

The length of a rectangle is 5 ft longer than its width.
If the perimeter of the rectangle is 30 ft, find its area.

Answer 1

Answer:

50 ft²

Step-by-step explanation:

If W is the width and L is the length, then:

L = W + 5

2L + 2W = 30

Solve the system of equations with substitution or elimination.  Using substitution:

2(W + 5) + 2W = 30

2W + 10 + 2W = 30

4W = 20

W = 5

L = 10

The area of the rectangle is:

A = LW

A = 50 ft²