Question

If someone throws a 3 gram fry accelerating at 5 meter/second2, what is the fry’s force?

Answer 1

The net force on the fry is 0.015 N.

Explanation:

We can solve this problem by using Newton's second law of motion, which states that:

$F=ma$

where

F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, we have a fry with mass

m = 3 g = 0.003 kg

And its acceleration is

$a=5 m/s^2$

Therefore, the net force acting on the fry is

$F=ma=(0.003)(5)=0.015 N$

Learn more about Newton's second law of motion:

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