Question

How many grams of CaF2 would be needed to produce 1.12 moles of F2?

Answer 1

Step 1 : Write balanced chemical equation.

CaF₂ can be converted to F₂ in 2 steps. The reactions are mentioned below.

I] $CaF_{2} + H_{2} SO_{4} -------> 2HF + CaSO_{4}$

II] $2HF -------> H_{2} + F_{2}$

The final balanced equation for this reaction can be written as

$CaF_{2} + H_{2} SO_{4} ---------> CaSO_{4} + H_{2} + F_{2}$

Step 2: Find moles of CaF₂ Using balanced equation

We have 1.12 mol F₂

The mole ratio of CaF₂ and F₂ is 1:1

$1.12mol F_{2} * \frac{1molCaF_{2}}{1molF_{2}} = 1.12molCaF_{2}$

Step 3 : Calculate molar mass of CaF2.

Molar mass of CaF₂ can be calculated by adding atomic masses of Ca and F

Molar mass of CaF₂ = Ca + 2 (F)

Molar mass of CaF₂ = 40.08 + 18.998 = 78.08 g

Step 4 : Find grams of CaF₂

Grams of CaF₂ = $1.12molCaF_{2} *\frac{78.08gCaF_{2}}{1mol CaF_{2}}$

Grams of CaF₂ = 87.45 g

87.45 grams of CaF2 would be needed to produce 1.12 moles of F2.

Answer 2

The amount of ${\text{Ca}}{{\text{F}}_2}$ needed to produce 1.12 moles of ${{\text{F}}_2}$ is $\boxed{{\text{87}}{\text{.4384 g}}}$ .

Further explanation:

Balanced chemical reaction:

The chemical reaction that contains equal number of atoms of the different elements in the reactant as well as in the product side is known as balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

Stoichiometry of a reaction is used to determine the amount of species present in the reaction by the relationship between the reactants and products. It can be used to determine the moles of a chemical species when the moles of other chemical species present in the reaction is given.

Consider the general reaction,

${\text{A}}+2{\text{B}}\to3{\text{C}}$  

Here,

A and B are reactants.

C is the product.

One mole of A reacts with two moles of B to produce three moles of C. Stoichiometric ratio between A and B is 1:2, the stoichiometric ratio between A and C is 1:3, and the stoichiometric ratio between B and C is 2:3.

The balanced chemical reaction between ${\text{Ca}}{{\text{F}}_2}$ and ${{\text{F}}_2}$ is as follows:

${\text{Ca}}{{\text{F}}_2}+{{\text{H}}_2}{\text{S}}{{\text{O}}_4}\to{\text{CaS}}{{\text{O}}_4}+{{\text{H}}_2}+{{\text{F}}_2}$

According to stoichiometry of the reaction, 1 mole of ${{\text{F}}_2}$ is produced by 1 mole of ${\text{Ca}}{{\text{F}}_2}$ .

Given number of moles of ${{\text{F}}_2}$  is 1.12 moles.

Therefore, number of moles of ${\text{Ca}}{{\text{F}}_2}$ will be equal to number of moles of ${{\text{F}}_2}$ and that is 1.12 moles.

Molar mass of ${\text{Ca}}{{\text{F}}_2}$ is 78.07 g/mol.

The formula to calculate mass of ${\text{Ca}}{{\text{F}}_2}$ is as follows:

${\text{Mass}}\left({\text{g}}\right) = {\text{number of moles}}\times{\text{molar mass of}}\;{\text{Ca}}{{\text{F}}_2}$     …… (1)

Substitute 1.12 mol for number of moles and 78.07 g/mol for molar mass of  ${\text{Ca}}{{\text{F}}_2}$ in equation (1).

$\begin{aligned}{\text{Mass}}\left({\text{g}}\right)&=\left({{\text{1}}{\text{.12 mol}}}\right)\left({{\text{78}}{\text{.07 g/mol}}}\right)\\&={\text{87}}{\text{.4384 g}}\\\end{aligned}$

Hence, the amount of ${\text{Ca}}{{\text{F}}_2}$ is 87.4384 g.

Learn more:

1. How many atoms are there in gaseous white phosphorus: https://brainly.com/question/9202946.

2. Determine atom with lowest atomic number in d shell: https://brainly.com/question/1915264.

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole concept

Keywords: Chemical reaction, reactant, product, number of moles, balanced chemical reaction, stoichiometry, CaF2, and 66.165 g.