Question

2019
Quiz: Chapter 6 Homework
According to recent surveys, 53% of households have personal computers. If a random
sample of 175 households is selected, what is the probability that more than 75, but
fewer than 110 have a personal computer? n-175 53 4​

Answer 1

Answer:

Step-by-step explanation:

n=175, p=0.53

q = 1–q = 1 – 0.53 = 0.47

Since np = (175)(0.53) = 92.75 and nq = (175)(0.47) = 82.25, the normal distribution can be used to

approximate the binomial distribution.

µ = np = (175)(0.53) = 92.75

σ = npq = (175)(0.53)(0.47) = 43.5925 = 6.60246

For binomial distribution, P(X > 75) and P(X < 110)

For normal distribution, P(75 + 0.5 < X < 110 – 0.5)

= P(75.5 < X < 109.5)