Question

Write a Lewis structure for OF2, then answer the following questions about the Lewis structure. 1. How many valence electrons does this compound have? 2. How many bonded electrons does this compound have? 3. How many lone pairs of electrons does this compound have? 4. How many single bonds does this compound have?

Answer 1

Answer :

(1) The number of valence electrons present in the compound is, 20

(2) The number of bonded electrons present in the compound is, 4

(3) The number of lone pair electrons present in the compound is, 16

(4) The number of single bonds present in the compound is, 2

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, $OF_2$

As we know that oxygen has '6' valence electrons and fluorine has '7' valence electrons.

Therefore, the total number of valence electrons in $OF_2$ = 6 + 2(7) = 20

According to Lewis-dot structure, there are 4 number of bonding electrons and 16 number of non-bonding electrons or lone pair of electrons.

The Lewis-dot structure of $OF_2$ is shown below.

Answer 2

From the structure of OF2 shown, there are two bond pairs and eight lone pairs in the molecule.

The Lewis structure of a molecule shows the number of valence electrons on each atom present in the molecule. Looking at the Lewis structures of compounds can help us to count the number of valence electrons in a molecule by counting the number of lone pairs and bond pairs present. OF2 has a total of 20 valence electrons.

There are four bonded electrons in this molecule and eight lone pairs. There are three lone pairs on each fluorine atom and two lone pairs on oxygen. There are two single bonds in the molecule.

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