Answer:
The final velocity of the car is 6.06 m/s in east.
Explanation:
Given that,
Total mass = 200 kg
Velocity = 5.40 m/s
Suppose we find the relative to the initial motion of the car
An object with the mass of 22.0 kg is thrown backward out of the car with a speed of 5.40 m/s relative to the initial motion of the car
We need to calculate the final velocity of the car
Using formula of relative motion
[tex]v=\dfrac{vm}{m-m_{1}}[/tex]
Put the value into the formula
[tex]v=\dfrac{5.40\times200}{200-22}[/tex]
[tex]v=6.06\ m/s[/tex]
Hence, The final velocity of the car is 6.06 m/s in east.