Respuesta :

[tex]\mathbf r(t)=\langle\sin t,\cos t,t\rangle\implies\mathbf r'(t)=\langle\cos t,-\sin t,1\rangle[/tex]

[tex]\mathbf f(x,y,z)=\langle x,-4y,-z\rangle\implies\mathbf f(x(t),y(t),z(t))=\langle\sin t,-4\cos t,-t\rangle[/tex]

[tex]\displaystyle\int_C\mathbf f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=3\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\mathbf r'(t)\,\mathrm dt[/tex]
[tex]=\displaystyle\int_{t=0}^{t=3\pi/2}(\sin t\cos t+4\sin t\cos t-t)\,\mathrm dt[/tex]
[tex]=\displaystyle\int_{t=0}^{t=3\pi/2}\left(\frac52\sin2t-t\right)\,\mathrm dt[/tex]
[tex]=\dfrac52-\dfrac{9\pi^2}8[/tex]
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